实现代码如下：

<?php
/**
 * php curl采集Discuz
 * www.
*/
set_time_limit(0);

//cookie保存目录
$cookdir = './cookie.tmp';

//模拟请求数据
Function request($url,$action,$cookdir,$referer){
    $ch = curl_init();
    $options = array(CURLOPT_URL => $url,
        CURLOPT_HEADER => 0,
        CURLOPT_NOBODY => 0,
        CURLOPT_PORT => 80,
        CURLOPT_POST => 1,
        CURLOPT_POSTFIELDS => $action,
        CURLOPT_RETURNTRANSFER => 1,
        CURLOPT_FOLLOWLOCATION => 1,
        CURLOPT_COOKIEJAR => $cookdir,
        CURLOPT_COOKIEFILE => $cookdir,
        CURLOPT_REFERER => $referer
    );
    curl_setopt_array($ch, $options);
    $code = curl_exec($ch);
    curl_close($ch);
    return $code;
}

//获取帖子列表
Function getList($code){
    //<a href="/blog_article/viewthread/tid/16/amp;extra/page/1.html">加打塔洗花腳本</a>
    preg_match_all('/<a href=/index.html"viewthread.php\?tid=(\d+)/',$code,$threads);
    return $threads[1];
}

//判断该帖子是否存在
Function isExits($code){
    preg_match('/<p>指定的主题不存在或已被删除或正在被审核，请返回。<\/p>/',$code,$error);
    return isset()($error[0])?false:true;
}

//获取帖子标题
Function getTitle($code){
    preg_match('/<h1>[^<\/h1>]*/',$code,$title_tmp);
    $title = $title_tmp[0];
    return $title;
}

//登录论坛/
$url = 'http://www./logging.php?action=login';
$action='/blog_article/loginfield=username&username=see7di&password=fjin999&questionid=0&cookietime=315360000&referer=http_/bbs.war3.cn/&loginsubmit=提交/index.html';
request($url,$action,$cookdir,'');
unset($action,$url);

//获取帖子列表(位于第一页的帖子)
$url = 'http://www./forumdisplay.php?fid=5';
$code = request($url,'',$cookdir,'');
$tList = getList($code);

//循环抓取每個帖子內的標題
foreach($tList as $list){
    $url = "http://www./viewthread.php?tid={$list}";
    $code = request($url,'',$cookdir,'');
    if(isExits($code)){
        $title = getTitle($code);
        echo "tid:{$list}:",strip_tags()($title),"<br>";
    }else{
        echo "tid:{$list}:该帖子不存在!<br>";
    }
}
?>

数据类似下面这样:
 

假如我post过来的cid值分别是4和5,那我如何精确的查询到id=4的这条数据?
同理,假如我post过来的cid值分别是4,5,7,8的时候,那我如何精确的查询到id=6的这条数据?

注意:
cid这一列的数据排列是非固定式的,没规律可循,唯一能够确认的就是不会重复出现同一个值
还有就是用like写法and链接这种方式我试过了,不够精确.例如...where cid like'%,4,%' and cid like'%,5,%'

解决方法:
分别用了三种方法做测试,测试的时候是循环20000次提取数据库里的数据,结果如下:
 

php实现模糊而又精确的查找就这么实现了，是不是很有意思呢？
以上就是今天php 教程的内容，希望本文给出的方法与思路，对大家有所帮助。

最常见的词语二分法:

<?php
$str = '这是我的网站www.！'; 
//$str = iconv('GB2312','UTF-8',$str); 
$result = spStr($str); 
print_r($result); 
   
/**
 * UTF-8版 中文二元分词
 */ 
function spStr($str) 
{ 
    $cstr = array(); 
   
    $search = array(",", "/", "\\", ".", ";", ":", "\"", "!", "~", "`", "^", "(", ")", "?", "-", "\t", "\n", "'", "<", ">", "\r", "\r\n", "{1}quot;", "&", "%", "#", "@", "+", "=", "{", "}", "[", "]", "：", "）", "（", "．", "。", "，", "！", "；", "“", "”", "‘", "’", "［", "］", "、", "—", "　", "《", "》", "－", "…", "【", "】",); 
   
    $str = str_replace()($search, " ", $str); 
    preg_match_all("/[a-zA-Z]+/", $str, $estr); 
    preg_match_all("/[0-9]+/", $str, $nstr); 
   
    $str = preg_replace("/[0-9a-zA-Z]+/", " ", $str); 
    $str = preg_replace("/\s{2,}/", " ", $str); 
   
    $str = explode()(" ", trim($str)); 
   
    foreach ($str as $s) { 
        $l = strlen($s); 
   
        $bf = null; 
        for ($i= 0; $i< $l; $i=$i+3) { 
            $ns1 = $s{$i}.$s{$i+1}.$s{$i+2}; 
            if (isset()($s{$i+3})) { 
                $ns2 = $s{$i+3}.$s{$i+4}.$s{$i+5}; 
                if (preg_match("/[\x80-\xff]{3}/",$ns2)) $cstr[] = $ns1.$ns2; 
            } else if ($i == 0) { 
                $cstr[] = $ns1; 
            } 
        } 
    } 
   
    $estr = isset($estr[0])?$estr[0]:array(); 
    $nstr = isset($nstr[0])?$nstr[0]:array(); 
   
    return array_merge($nstr,$estr,$cstr); 
}
?>

結果是:
Array ( [0] => www [1] => xxx [2] => net [3] => 这是 [4] => 是我 [5] => 我的 [6] => 的网 [7] => 网站 )

如果以上结果转换为区位码，则如下代码所示：

<?php
foreach ($result as $s) { 
    $s = iconv('UTF-8','GB2312',$s); 
    $code[] = gbCode($s); 
} 
$code = implode(" ", $code); 
echo $code; 
   
function gbCode($str) { 
    $return = null; 
   
    if (!preg_match("/^[\x80-\xff]{2,}$/",$str)) return $str; 
   
    $len = strlen($str); 
    for ($i= 0; $i< $len; $i=$i+2) { 
        $return .= sprintf()("%02d%02d",ord($str{$i})-160,ord($str{$i+1})-160); 
    } 
   
    return $return; 
}
?>